Formula for the Riemann Tensor Components (RTC)

 for orthogonal metrics of any dimensionality. [1]      Air1@nyu.edu   

 

Notation

 

For an orthogonal metric of any dimensionality we can write:

 

ds2 = gaadxadxa    (summed on a)

We define: g D   |gDD|  ;  No summation over D: to indicate this in the following we will insert [NS])

 

We also define hD  and wD via:

 

wD =  gDdx D (No summation over D [NS: D])

 

ds2  ha (wa) 2   ha [ga]2 [dxa]2.  (summed over a: summation will be assumed in the below unless NS is specifically indicated) [The ha contain the signature information.]         (1)              [2]

………

2-d and Gaussian Curvature

For a 2-d surface, using an orthogonal coordinate system (xA, xB), the  metric is:

 

ds2 = gAAdxA ² + gBBdxB ²    (no sum on A or B [NS: A,B]).

Gauss’s curvature formula for this surface is: [See Barrett O’Neill: “Semi Riemannian Geometry” p81]

 

KAB  =  - [gA gB]-1{hA [gA,B /gB],B  + hB[gB,A/gA],A}    [NS: A,B].

The Gaussian curvature arises from the interconnection of the two dimensions represented by the coordinates corresponding to the two indices of K (or of the metric coefficients corresponding to the coordinates). Quantitatively, the Gaussian curvature arises via – or is dependent - the derivatives of the metric coefficient corresponding to one coordinate, derived w/r/t the other coordinate. In this sense the Gaussian curvature is the curvature arising from a “mutual” interconnection. (Then a second derivative is formed, giving rise to second order terms.)

Intrinsic Curvature: The above formula also provides the intrinsic curvature of a 2-d space described by the above metric.

 

Intrinsic Curvature for 3-d and higher

The formula for the Riemann Tensor Components (RTCs) for orthogonal metrics of any dimensionality is the Gauss term above plus an additional term which we call the ‘intermediary term’ I: 

 

              IAB =  hDhB (hA)  gD-2 [gA,D/gA][gB,D/gB] D A,B          (summed on D A,B)

=  [gA gB]-1    hDhB (hA)  gD-2 [gA,D][gB,D] D A,B

This term vanishes unless both of the metric coefficients corresponding to the indices of the RTC have non-vanishing derivatives w/r/t the same coordinate(s). We will term “intermediary coordinates” those coordinates w/r/t which both of the metric coefficients corresponding to the indices of the RTC have non-vanishing derivatives. We can then say that this term relates to the curvature arising from the interconnection of the two dimensions represented by A and B via the dimensions represented by the “intermediary coordinates”.

 

We can therefore write:     (Note: No Sum on A,B. However, D summed on DA,B)

RABAB  =  KAB  + IAB = - [gA gB]-1{ [gA,B /gB],B  + hA hB[gB,A/gA],A + hDhB (hA)gD-2 [gA,D][gB,D] D A,B }

 

Where the first (Gaussian) part of the RTC is the curvature arising from the “mutual” interconnection, and the ‘additional’ (third) term is the curvature arising from the interconnection via the “intermediary” dimensions/coordinates.

 

·          The terms are manifestly symmetric under A ßà B.  [(AR to AR: check the signature part of the last term)] Note that this is not true of the usual formulae for the RTC.

·        This division of the RTC into “mutual” and “intermediary” terms grants this form of the RTC formula a certain intuitive basis.

·        Use of this formula facilitates intuiting shortcuts in calculations of the RTC. (Some RTCs can be computed mostly ‘by inspection’ using this formula; the terms arising in the RTCs can be easily traced to the metric; some properties of special metrics are easily discernible eg for metrics with inverse relationship eg: gtt = -grr-1  [Rtt is a Laplacian]).

 

……………..

Derivation of the above RTC Formula

Introduction

 

We wish to find the Riemann tensor components (RTCs) RABAB from the formula for the curvature two-form:

 

                                         Term #1     Term #2

RAB  =  dwAB    -   wAD^ wDB        (see eg MTW p351)                (2a)

 

= - RAB|EF|  wE ^ wF          (E<F)                  (see eg MTW p352)

The (A,B,E,F) RTCs are obtained as the coefficients of wE ^ wF  .

With two raised indices: 

RAB  = - RAB|EF|  wE ^ wF      (see eg MTW p358)                            (2b)

= - RABAB  wA ^ wB  (NS:A,B)   - RABAD  wA ^ wD (D>A) - RABDB  wD^ wB   (D<B) - RABCE  wC^ wE  (C,EA,B)

For orthogonal metrics, we will be interested in calculating the RTCs with repeating indices, ie the RABAB (NS: A,B)  [3]  and so we seek the coefficient of the term wA ^ wB  . To do so we begin below with a calculation of wAB from which we will compute both terms in eq (2a)  {ie: dwAB (term #1) and wAD^ wDB  (term #2)}.

 

A) Computation of wAD:     footnote [4]              

 

For the specific coordinate xA: [A:NS]

 

dwA = d[gAdxA]       [A:NS]

=  d[gA]dxA + gA ddxA  = gA,D dxD^dxA   DA

 

= gA,D wD/gD ^ wA/gA  =  [gA,D/(gDgA)] wD ^ wA      D A.                   (3)

 

However we also know that:

 

dwA = - wAD^ wD  D A   =   + wD ^ wAD       D A             [5]               (4)

 

By equating (3) and (4) we obtain:

 

wD ^ wAD     D A = wD ^ wA  [gA,D/(gDgA)]   [D not=A]                  (5)

 

 The first impression is that

 

wAD = wA  [gA,D/(gDgA)]   [D not=A] 

however since by definition

  wD ^ wD     = 0

 

we can add a term proportional to wD without affecting matters, ie:

 

[wA + f wD] ^ wD =   wA ^ wD

 

(where f is a function of the coordinates, we’ll signify it’s unknown nature by writing it below as [?] )

 

ie the more general solution of equation (5) above  is:

 

wAD = [gA,D/(gDgA)] wA + [?] wD          (5b)

 

where [?] signifies an unknown term to be determined below.

Note that whereas A is a specific coordinate, D is summed over all coordinates other than A, and so for each coordinate value of D there will be a companion term: [?] wD .

 

We now switch A ßà D to obtain:

 

wDA= [gD,A/(gAgD)] wD  + [?] wA                  (5c)

 

We also know that:

wAD =  - wDA hA hD  . D A            

 We will assume from this point on that we sum over all values of D except for A.

 

Therefore: 

wAD = [gA,D/(gDgA)] wA + [?] wD

=  - wDA hA hD

 =  -   hA hD  { [gD,A/(gAgD)] wD  + [?] wA }

 

So we can set:

                        [?] wD =  -   hA hD  [gD,A/(gAgD)] wD                                                                    (5d)       

 

-   hA hD  [?] wA  =  [gA,D/(gDgA)] wA                 Footnote [6]

 

Therefore inserting [?] wD from (5d) into (5b) we can write the connection two-form as:

 

 wAD =  [gA,D/(gDgA)] wA  -  hA hD  [gD,A/gAgD)] wD                          Footnote   [7]

        

         =  [gAgD] -1 {gA,D wA   -  hA hD gD,A wD}     .                                 (6A1)      

Written in terms of dx:

wAD  =  [gAgD] -1 {gA,D gAdxA -  hA hD gD,A gD dxD }                                            (6A2)      

wAD =  [gA,D/gD] [dxA]  -  hA hD [gD,A/gA][dxD]   .        (6c)

 

·        Note the symmetry of the two terms in A and D (other than for the signature symbols).

·        Note from (6A1) that if both gA,D and gD,A are zero then wAD = 0.  This makes geometric sense: if both of these derivatives vanish, there is clearly no direct ‘connection’ between the coordinates A and D. Often we will find that the two metric coefficients gA and gD are functions of only one of the coordinates (A,D), not both, and so one of the two terms in (6) vanishes.

 

Significance of the above equation:

·        The above formulation allows use of a closed form of  wAD for all further computations!

·         The development up to this point displays in a transparent manner the origin of each term in wAD.

……………………….

 

·        Note the relationship to the connections of the terms like gA,D/gD in the connection two-form:

GDAA = gAA,D/[-2gDD] = [hAgA²],D/[-2hDgD²] = 2hAgAgA,D/[-2hDgD²]

= -hDhA [gA/gD][gA,D/gD]

If we define:

GDAA  [gA,D/gD]

then we can write this as:

GDAA = -hDhA [gA/gD] GDAA        .               [8]

…………………………………………….

B)  Computation of   wAD ^ wDB 

 

From equation (6A1)  wAD  =  [gAgD] -1 {gA,D wA   -  hA hD gD,A wD}                (NS: A)

we can write:

 

wAD ^ wDB   [D A,B]

 

    = [gAgD] -1{gA,D wA -  hA hD gD,A wD} ^ [gBgD] -1{gD,B wD -  hD hB gB,D wB}     (NS: A,B)           (7a)

[As a check: wAD and wDB have the same form, but with (A,D) à (D,B) ie [A à D,  Dà B] .

 

We combine the two products [gAgD] -1 and [gBgD] –1 :

 [gAgD] -1 [gBgD] –1 = [gAgDgBgD] –1 = [gAgBgD2] -1

so that we can write:

wAD ^ wDB   [D A,B]   = [gAgBgD2] -1{gA,D wA -   hA hD gD,A wD} ^ {gD,B wD -  hD hB gB,D wB}        

                                                                           Term:                   #1                   #2                               #3                      #4

 

Multiplying the terms in eq. (7a) will give us these products: 

(1) x (3)  +  (1) x (4)  +  (2) x (3)  +  (2) x (4)

 

Note that:

·         (2) x  (3) = 0 because both have wD : 

·         in (2) x (4) one has – x – = + , and hD hD = 1  , leaving only hAhB;

 

Therefore: 

wAD ^ wDB     D A,B        (NS: A,B)  = (1) x (3)  +  (1) x (4)  +  (2) x (4)

= [gA gB gD2]-1{gA,D gD,B wA ^ wD -  hDhB gA,D gB,D wA ^ wB + hAhB gD,A gB,D wD^wB}D A,B           (7b)

 

Note that the above is term #2 in eq (2a) copied below:

RAB  =  dwAB  -   wAD^ wDB        (see eg MTW p351)                                      (2a)

 

C) Computation of   d wAB  

 

wAB =  [gA,B/gB] [dxA]  -  hA hB [gB,A/gA][dxB]   .        (eq 6c with: D à B)

From equation 6c above we find: 

 

d wAB  =  [gA,B /gB],c dxC ^ dxA   C A       - hA hB [gB,A/gA],c dxC ^ dxB    C  B                  (8a)    (NS: A,B)

Changing the order of the first wedge product, and therefore changing the sign:

d wAB  = - [gA,B /gB],c dxA ^dxC  CA       - hA hB [gB,A/gA],c dxC ^ dxB   C  B                                     (8a)    (NS: A,B)

Note that in order to take the derivatives we employed eq 6C with dxA rather than 6A with  wA ; however now that we have the derivative we can put this back into terms of wA and wB:

 

 

d wAB  = -[gAgC]-1[gA,B /gB],cwA ^wC C A     - hA hB[gC gB]-1[gB,A/gA],c wC ^ wB   C B                     (8b)

                                Term    #1                                                            Term    #2

 

 

Note:

·         In the first term’s sum over C,  C cannot be A, but since B is NOT A, C CAN be B.

·          when in the first term C = B, and in the second term C = A both terms contain wA ^ wB.

·          In the above case, [gB gA]-1  is a common factor.

 

For term #1: We separate out the case C = B and C  B.

For term #2: we separate below the cases C = A, and CA.                     (NS: A,B)

 

          d wAB   =    a) Term #1 with C = B    à      -[gA gB]-1  [gA,B /gB],B wA ^ wB 

                                   b) + Term #1 with C  B   à    - [gA gC]-1[gA,B /gB],c  wA ^ wC     C  A,B                   

c) + Term #2 with  C = A   à    - hA hB [gA gB]-1  [gB,A/gA],A  wA ^ wB

                d)   + Term #2 with C  A à   - hA hB[gC gB]-1[gB,A/gA],c wC ^ wB   C  A,B         

 Collecting terms with the same wedge products:

a) and c) have the same wedge: also, [gA gB]-1  is a common factor: so:

a) + c)  =  -[gA gB]-1 {[gA,B /gB],B + hA hB [gB,A/gA],A]  wA  ^ wB

In d), switching wC ^ wB   to wB ^ wC  so that we need to introduce a ‘-‘, and then adding to b): 

b) + d)  =  - gC-1 {gA-1[gA,B /gB],c  wA    - hA hB [gB]-1[gB,A/gA],c wB }^ wC   C  A,B

 and so we can write: note: we change the summation index from C to D:

d wAB   =  - [gA gB]-1 { [gA,B /gB],B +  hA hB [gB,A/gA],A }  wA ^ wB  +

- {[gA gD]-1[gA,B /gB],D  wA - hA hB[gD gB]-1[gB,A/gA],D wB}^ wD    D A,B      (NS: A,B)             (8c)  

Note that the above is term #1 in eq (2a) [rewritten below].       

RAB  =  dwAB  -   wAD^ wDB        (see eg MTW p351)                                      (2a)

 

D) Finding the Riemann tensor components (RTCs)

 

Inserting the results of equations (7b) and (8c) into eq. (2): (we use the summation index D):(NS: A,B)

 

RAB  =  dwAB  -   wAD^ wDB =  - RABAB  wA ^ wB  - RABAD  wA ^ wD - RABDB  wD^ wB

=  -[gA gB]-1{[gA,B /gB],B + hA hB[gB,A/gA],A}wA^wB       

 {-[gA gD]-1[gA,B /gB],D  wA + hA hB[gD gB]-1[gB,A/gA],D wB}^ wD    D A,B

- [gAgBgD2]-1{gA,D gD,B wA ^ wD - hDhB gA,DgB,D wA ^ wB + hAhB gD,A gB,D wD^wB}D A,B

We now collect terms with the same wedge products:

 

Note the three terms in wA ^ wB : (the first two, and the second-to-last): adding them gives:

 

-[gA gB]-1{[gA,B /gB],B + hA hB[gB,A/gA],A}wA^wB     - {[gAgBgD2]-1 (-) hDhB gA,DgB,D wA ^ wB }D A,B

Distributing the common wA^wB   and - [gA gB]-1  gives us:

- [gA gB]-1    { [gA,B /gB],B + hA hB[gB,A/gA],A - gD-2 hDhB gA,DgB,D }wA ^ wB  D A,B

Note that there are only two terms in wB^ wD:

 

1) -  hA hB[gD gB]-1[gB,A/gA],D wB^ wD    D A,B

2)  - [gAgBgD2]-1 hAhB gD,A gB,D wD^wB  D A,B  

=   hAhB [gDgBgAgD]-1 gD,A gB,D wB ^ wD D A,B

Terms 1) and 2) have  hAhB [gDgB]-1 wB ^ wD in common, and so adding 2) + 1) gives:

 

 hAhB [gDgB]-1 {[gAgD]-1 gD,A gB,D  - [gB,A/gA],D}   wB ^ wD

 

so we find: 

 

RAB  =  - [gA gB]-1    { [gA,B /gB],B + hA hB[gB,A/gA],A - gD-2 hDhB gA,DgB,D }wA ^ wB  D A,B

 

+  hAhB [gDgB]-1 {[gAgD]-1 gD,A gB,D  + [gB,A/gA],D}   wB ^ wD

 

 

             - gA -1{gD-1 [gA,B /gB],D + [gBgD2] -1 gA,D gD,B}  wA ^ wD        D A,B

 

=  - RABAB  wA ^ wB  - RABAD  wA ^ wD - RABDB  wD^ wB

Therefore:

 

RABAB    =  + [gA gB]-1  { [gA,B /gB],B + hA hB[gB,A/gA],A - gD-2 hDhB gA,D gB,D }

=  +  [gA gB]-1{[gA,B /gB],B  + hA hB[gB,A/gA],A}   -  hDhB gD-2 [gA,D/gA][gB,D/gB] D A,B

 

Note that the third term seems non-symmetric since only hDhB appear without hA. However we can see that this must be the case since the h’s appear in pairs, their presence makes a difference only if one of A or B is t, so that the product is – (whatever the choice of signature). If one or the other is t, then hA hB is necessarily –1 and the sum of the first two terms become the negative of its sum under interchange A à B. If the third term had hA hB in it then this third term would not change sign under A à B, so therefore it must have only one of them, and has one sign if A is t and another sign if B is t. ie when there are two terms involved as in the first part of RABAB, the switch in sign can be overall by both terms conspiring to switch together, but for one term {the [gA,D/gA][gB,D/gB] term} the sign switch can happen only if there’s an h for only one of the two coordinates.

………..

Note:

…………

Note:

Similarly (check signs):

 

RABBD    =  -  hAhB [gDgB]-1 {[gAgD]-1 gD,A gB,D  + [gB,A/gA],D}

        RABAD    =   - gA -1{gD-1 [gA,B /gB],D + [gBgD2] -1 gA,D gD,B}  wA ^ wD        D A,B

 

……………………………….

 

Appendix

Post-Hoc Heuristic ‘Derivation” of the repeated-index RTC

 

A)    Finding wAD:   

              

From the way that the switching of upper to lower indices of wAD changes the sign as follows:

 

wAD =  - wDA hA hD  . D A            

we can justify the following structure for wAD:

 

 wAD =  [gA,D/(gDgA)] wA  -  hA hD  [gD,A/gAgD)] wD                     

                 =  [gAgD] -1 {gA,D wA   -  hA hD gD,A wD}           .                                 (6A1)      

Written in terms of dx: ie: wA = gAdxA ; wD = gD dxD :

wAD  =  [gAgD] -1 {gA,D gAdxA -  hA hD gD,A gD dxD }                                            (6A2)      

wAD =  [gA,D/gD] [dxA]  -  hA hD [gD,A/gA][dxD]   .        (6c)

 

B)  Computation of  the ‘wedge product’  wAD ^ wDB 

 

To form wDB we simply transform wAD above by switching (A,D à D,B) ie (AàD), (DàB), so that the first term is in wD and the second has wB . Creating the ‘wedge product’ of the two will lead to only one term with wA ^ wB , basically from the product of the first term of wAD (which has wA) with the second term of wDB (which has wB); ie

 

[gA,D wA ] ^ [- hD hD gB,D wB] =  - hD hB  gA,D gB,D  wA  ^ wB

with a factor of [gg] –1 for both. Thus the relevant part wAD ^ wDB  of is:

 

- hD hB  gA,D gB,D [gAgD] -1[gDgB] -1 wA  ^ wB     D A,B   

= - hDhB gD-2 [gA,D/gA][gB,D/gB] D A,B                      (7e)

C) d wAB   :

d wAB  = - [gA,B /gB],c dxA  ^dxC  CA       - hA hB [gB,A/gA],c dxB ^ dxC   C  B                                     (8a)    (NS: A,B)

= - [gA,B /gB],c   [wA/gA] ^ [wC/gC]  CA       - hA hB [gB,A/gA],c   [wB/gB] ^ [wC/gC]  C  B

The terms of interest are for C = B in the first term, and for C = A in the second, which makes wA ^ wB   a common factor, and turns the gi’s under the wi’s , ie both gA gC and gBgC into gAgB and thereby makes [gAgB]-1 , a common factor as well. Distributing these common factors we have:

 

d wAB  =  - [gA gB]-1 {[gA,B /gB],B - hA hB [gB,A/gA],A}wA ^ wB                   (8c)   (NS: A,B)

Note that the above is the (ABAB) part of term #1 in eq (2a).       

RAB  =  dwAB  -   wAD^ wDB        (see eg MTW p351)                                      (2a)

 

D) The (ABAB) Riemann tensor component (RTCs)

 

Therefore, adding (7e) and (8c) we obtain::

 

RABAB    =  +  [gA gB]-1{[gA,B /gB],B  + hA hB[gB,A/gA],A} - hDhB gD-2 [gA,D/gA][gB,D/gB] D A,B                                                   

 



[1] From file “My RTC Formula derivation 2005”.

[2] Note: Since I define a one-index quantity gm = sqrt|gmm| , it is of interest to see that Landau Lifschitz (LL): p277: uses a similar notation for something else: ga = g0a , where a  are the spatial indices only.

 [Also: tetrad notation in field theory, and tetrad formulation of GR in field theory.]

 

[3] AR to AR: show that only these exist, or are needed to set up or solve the Einstein equation.

[4] For the calculation below: note that by definition, operating twice with d, ie dd, gives zero.

[5]  If D = A:  wAA = -  wAA = - hA hA  wAA = - hA 2  wAA = -  wAA ,  So we do not allow D = A.

 

[6] Since - hA hD  is simply a sign, it can be transferred from the rhs to the lhs without change. As a result one can easily see that these two equations are the same, they are consistent, since interchanging D and A transforms one into the other.

[7] Remember that D will be summed over, and each wD will have the appropriate sign due to the accompanying  hD .

[8] Note also that (see MTW p354): wAD gANwND = GADNwN .   

 


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